PROG SKILL (204) Set A - Practical Solutions

Paper Information

Attribute	Value
Subject	Programming Skills Using C
Subject Code	204 (PROG SKILL)
Set	A
Exam Type	Practical
Max Marks	25
Month/Year	April 2024

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Question 1: Student Structure with Total and Percentage

Question 1: Create Structure and Calculate

Q: Write a program to create a structure of five student with a member name, roll no, 3 subject marks calculate total and percentage display it proper format.

Requirements: - Create structure with: name, roll_no, 3 subject marks - Calculate total marks - Calculate percentage - Display in proper format - Handle 5 students

Solution - C Language

#include <stdio.h>
#include <string.h>

// Define structure for student
struct Student {
    char name[50];
    int roll_no;
    int marks[3];
    int total;
    float percentage;
};

int main() {
    struct Student s[5];
    int i, j;

    // Input data for 5 students
    printf("Enter details for 5 students:\n\n");
    for(i = 0; i < 5; i++) {
        printf("Student %d:\n", i + 1);

        printf("Enter Name: ");
        scanf(" %[^\n]", s[i].name);

        printf("Enter Roll No: ");
        scanf("%d", &s[i].roll_no);

        printf("Enter 3 Subject Marks: ");
        for(j = 0; j < 3; j++) {
            scanf("%d", &s[i].marks[j]);
        }

        // Calculate total
        s[i].total = 0;
        for(j = 0; j < 3; j++) {
            s[i].total += s[i].marks[j];
        }

        // Calculate percentage
        s[i].percentage = s[i].total / 3.0;

        printf("\n");
    }

    // Display results in proper format
    printf("\n========================================\n");
    printf("     STUDENT MARKSHEET - SET A\n");
    printf("========================================\n\n");

    printf("%-5s %-15s %-8s %-10s %-12s %-12s\n", 
           "No", "Name", "Roll", "Total", "Percentage", "Grade");
    printf("-------------------------------------------------------------\n");

    for(i = 0; i < 5; i++) {
        char grade;
        if(s[i].percentage >= 80) grade = 'A';
        else if(s[i].percentage >= 60) grade = 'B';
        else if(s[i].percentage >= 40) grade = 'C';
        else grade = 'F';

        printf("%-5d %-15s %-8d %-10d %-12.2f %-12c\n",
               i + 1, s[i].name, s[i].roll_no, 
               s[i].total, s[i].percentage, grade);
    }

    printf("=============================================================\n");

    return 0;
}

Expected Output - C

Enter details for 5 students:

Student 1:
Enter Name: Rahul
Enter Roll No: 101
Enter 3 Subject Marks: 85 90 88

Student 2:
Enter Name: Priya
Enter Roll No: 102
Enter 3 Subject Marks: 78 82 80

Student 3:
Enter Name: Amit
Enter Roll No: 103
Enter 3 Subject Marks: 92 88 95

Student 4:
Enter Name: Sita
Enter Roll No: 104
Enter 3 Subject Marks: 75 80 78

Student 5:
Enter Name: Ram
Enter Roll No: 105
Enter 3 Subject Marks: 88 85 90

========================================
     STUDENT MARKSHEET - SET A
========================================

No    Name            Roll     Total      Percentage   Grade       
-------------------------------------------------------------
1     Rahul           101      263        87.67        A           
2     Priya           102      240        80.00        A           
3     Amit            103      275        91.67        A           
4     Sita            104      233        77.67        B           
5     Ram             105      263        87.67        A           
=============================================================

Solution - Python

# Student data structure using dictionary
students = []

# Input data for 5 students
print("Enter details for 5 students:\n")
for i in range(5):
    print(f"Student {i + 1}:")

    name = input("Enter Name: ")
    roll_no = int(input("Enter Roll No: "))

    print("Enter 3 Subject Marks (space separated): ", end="")
    marks = list(map(int, input().split()))

    # Calculate total and percentage
    total = sum(marks)
    percentage = total / 3

    # Store student data
    student = {
        'name': name,
        'roll_no': roll_no,
        'marks': marks,
        'total': total,
        'percentage': percentage
    }
    students.append(student)
    print()

# Display results in proper format
print("\n" + "=" * 60)
print("     STUDENT MARKSHEET - SET A")
print("=" * 60 + "\n")

# Header
print(f"{'No':<5} {'Name':<15} {'Roll':<8} {'Total':<10} {'Percentage':<12} {'Grade':<10}")
print("-" * 60)

# Student data
for i, s in enumerate(students, 1):
    # Determine grade
    if s['percentage'] >= 80:
        grade = 'A'
    elif s['percentage'] >= 60:
        grade = 'B'
    elif s['percentage'] >= 40:
        grade = 'C'
    else:
        grade = 'F'

    print(f"{i:<5} {s['name']:<15} {s['roll_no']:<8} "
          f"{s['total']:<10} {s['percentage']:<12.2f} {grade:<10}")

print("=" * 60)

Expected Output - Python

Enter details for 5 students:

Student 1:
Enter Name: Rahul
Enter Roll No: 101
Enter 3 Subject Marks (space separated): 85 90 88

Student 2:
Enter Name: Priya
Enter Roll No: 102
Enter 3 Subject Marks (space separated): 78 82 80

Student 3:
Enter Name: Amit
Enter Roll No: 103
Enter 3 Subject Marks (space separated): 92 88 95

Student 4:
Enter Name: Sita
Enter Roll No: 104
Enter 3 Subject Marks (space separated): 75 80 78

Student 5:
Enter Name: Ram
Enter Roll No: 105
Enter 3 Subject Marks (space separated): 88 85 90

============================================================
     STUDENT MARKSHEET - SET A
============================================================

No    Name            Roll     Total      Percentage   Grade     
------------------------------------------------------------
1     Rahul           101      263        87.67        A         
2     Priya           102      240        80.00        A         
3     Amit            103      275        91.67        A         
4     Sita            104      233        77.67        B         
5     Ram             105      263        87.67        A         
============================================================

Explanation

C Language: - struct Student defines a blueprint with name, roll_no, marks array, total, and percentage - s[5] creates an array of 5 student structures - Nested loops handle input and calculations for all 5 students - scanf(" %[^\n]", ...) reads string with spaces for names - Grade is determined using simple if-else conditions

Python: - Dictionary stores each student's data with clear key-value pairs - list(map(int, input().split())) efficiently reads 3 marks in one line - sum(marks) calculates total automatically - Formatted string literals (f-strings) create clean table output - Grade logic identical to C version

Concept Deep Dive: Structures vs Dictionaries

C Structure: - Groups related data under one name - Memory-efficient, contiguous storage - Requires manual memory management for strings - Compile-time type checking

Python Dictionary: - Dynamic, flexible key-value storage - Automatic memory management - No fixed schema - can add/remove keys - Runtime type checking

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Question 2: Viva Preparation

Question 2: Viva + Journal

Q: Viva + Journal (5 Marks)

Be prepared to explain: - Your program logic - Structure/Dictionary concepts - Calculation methodology

Potential Viva Questions

Q1: What is a structure in C? - A: A structure is a user-defined data type that groups related variables of different types under a single name. It allows organizing complex data efficiently.

Q2: Why use an array of structures instead of separate variables? - A: An array of structures allows handling multiple records efficiently with loops, reduces code repetition, and makes data management organized.

Q3: How is percentage calculated? - A: Percentage = (Total marks obtained / Maximum possible marks) × 100. Here, total = sum of 3 subjects, max = 300, so percentage = total/3.

Q4: What is the difference between structure and array? - A: Array stores elements of same data type with contiguous memory. Structure stores elements of different data types grouped together under one name.

Q5: Explain the format specifiers used in printf. - A: %s for string, %d for integer, %f for float, %.2f for float with 2 decimal places, %c for character, - for left alignment, number for width.

Common Pitfalls

• Buffer overflow: Ensure name array size (50) is sufficient
• Integer division: Use 3.0 instead of 3 for accurate percentage
• Input buffer: Use space before %[^\n] to clear buffer
• Array bounds: Always check marks array index stays 0-2
• Format alignment: Match width specifiers with actual data length

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